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Weierstrass product inequality : ウィキペディア英語版
Weierstrass product inequality
In mathematics, the Weierstrass product inequality states that given real numbers 0 ≤ ''a'', ''b'', ''c'', ''d'' ≤ 1, it follows that
:(1-a)(1-b)(1-c)(1-d)+a+b+c+d \geq 1. \,
The inequality is named after the German mathematician Karl Weierstrass.


抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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